Going from int to std::string to char* isn't the same as int to char*.
char is just a 1 byte integer. There is nothing magic with the char type! Just as you can assign a short to an int, or an int to a long, you can assign a char to an int.
char[50]; is array of 50 elements of type char. Each element has type char. So new char[50]; returns a pointer to first element: char * - pointer to char.
char *name[NAME_LEN]; is an array of pointers, not array of characters.So when you call strcpy(t->name, name); t->name becomes of type char** instead of char*.
char char_arr [100]; int num = 42; sprintf(char_arr, "%d", num); char_arr now is the string "42". sprintfautomatically adds the null character \0 to
void StuffIntIntoChar4(char (&pIntoChar4)[4], int32_t val); Second, you are running into undefined behavior. In the C++11 standard (section [expr.shift]), it says.
When compiler sees the statement: char arr[] = "Hello World"; It allocates 12 consecutive bytes of memory and
Нужно проверить обычный CHAR (ну и индекс добавим, мало ли что...) Тест №3
Now I want convert p(char *) to pwcsName(WCHAR *). Can anybody suggest me how do this? Is it done using "mbtowc" function or MultiByteToWideChar...
2. easiest way to append char - using simple assignment.