The expression UChar( c ) converts to unsigned char in order to get rid of negative values, which, except for EOF, are not supported by the C functions. Then the result of that expression is used as actual argument for an int formal argument. Where you get automatic promotion to int.
Going from int to std::string to char* isn't the same as int to char*.
This question already has answers here: Converting int to char in C (7 answers).
char *name[NAME_LEN]; is an array of pointers, not array of characters.So when you call strcpy(t->name, name); t->name becomes of type char** instead of char*.
I have a char that is given from fgets, and I would like to know how I can convert it into a char*. I am sure this has been posted before, but I couldn't
I know that for cannot convert char to char * you just use the & in front of the char, but I cannot figure out what to do in this case.
Actually, it doesn’t convert the datatype of <char> (assuming it’s a variable), although the result
Рассматривается один из способов перевода цифры из целочисленного типа int в символьный тип char в языке программирования Си.
2. easiest way to append char - using simple assignment.