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c - Array of char* should end at '\0' or "\0"? - Stack Overflow
You're comparing a char * to a char *, yes, but this comparison is meaningless. It passes if the two pointers point to the same piece of memory. You can't use == to compare two strings, you have to use the strcmp() function, because C has no built-in support for strings outside of a few (and I mean few)...
Convert char to int in C and C++ - Stack Overflow
char c = somevalue; signed char sc = c; unsigned char uc = c; int n = c; But, when somevalue is outside of that range, only going through unsigned char gives you consistent results for the
c - append a character from an array to a char pointer - Stack Overflow
If you use a char array (your buffer) big enough to hold your characters, you can still modify its content : #include <stdio.h>.
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array - Difference between char and char* in c - CS50 Stack Exchange
char[] is a structure, it is specific section of memory, it allows for things like indexing, but it always will start at the address that currently hold's 'h'. char* is a variable. It was initialize with a number, but we can change number using mathematical operators such as ++, because it is essentially an integer.
Strings - The Basics of C Programming | HowStuffWorks
char str[100]; It holds characters as you would expect: str[0] is the first character of the string, str[1] is the second character, and so on.