How can I prepend char c to char* myChar? I have c has a value of "A", and myChar has a value of "LL".
Handling all three char types (signed, unsigned, and char) is more delicate than it first appears.
The terminology is important here, I think. The char ** doesn't "hold" a series of strings at all (unlike container objects in higher-level languages than C). The variable c is just a pointer to a pointer to a character, and that character is going to be the first character in a nul-terminated string.
You're comparing a char * to a char *, yes, but this comparison is meaningless. It passes if the two pointers point to the same piece of memory. You can't use == to compare two strings, you have to use the strcmp() function, because C has no built-in support for strings outside of a few (and I mean few)...
Длина строки char array. Массив строк. F() macro. Экономия памяти. Инструменты для char array.
2. easiest way to append char - using simple assignment.
int begin(char* ssid, const char *passphrase); ^ exit status 1 invalid conversion from 'const char*' to
num_var = 123456; char_var = put(num_var,6.); When you start with a numeric value, the resulting string is right-aligned by default.
The type of both the variables is a pointer to char or (char*), so you can pass either of them to a function whose formal argument accepts an array of characters or a character pointer.
Нужно проверить обычный CHAR (ну и индекс добавим, мало ли что...)