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You can convert a char type simply by assigning to an int.
Going from int to std::string to char* isn't the same as int to char*.
char *name[NAME_LEN]; is an array of pointers, not array of characters.So when you call strcpy(t->name, name); t->name becomes of type char** instead of char*.
char[50]; is array of 50 elements of type char. Each element has type char. So new char[50]; returns a pointer to first element: char * - pointer to char.
However, an error comes: Cannot convert 'char(*)[50]' to 'char**' for argument '1' to 'void prac(char**)'. How can I fix the code ? Please help me.
I have a char that is given from fgets, and I would like to know how I can convert it into a char*. I am sure this has been posted before, but I couldn't
Рассматривается один из способов перевода цифры из целочисленного типа int в символьный тип char в языке программирования Си.
Now I want convert p(char *) to pwcsName(WCHAR *). Can anybody suggest me how do this? Is it done using "mbtowc" function or MultiByteToWideChar...
Нужно проверить обычный CHAR (ну и индекс добавим, мало ли что...) Тест №3